v^2+v=1.25

Solution for v^2+v=1.25 equation:

v^2+v=1.25

We move all terms to the left:

v^2+v-(1.25)=0

We add all the numbers together, and all the variables

v^2+v-1.25=0

a = 1; b = 1; c = -1.25;
Δ = b2-4ac
Δ = 12-4·1·(-1.25)
Δ = 6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{6}}{2*1}=\frac{-1-\sqrt{6}}{2}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{6}}{2*1}=\frac{-1+\sqrt{6}}{2}
$